Coding Test/Practice
백준 1697번 숨바꼭질 JavaScript 풀이 [BFS]
yunicornlab
2024. 7. 21. 21:29
백준 1697번 숨바꼭질 문제를 자바스크립트로 BFS 알고리즘을 이용해서 풀어보았다.
https://www.acmicpc.net/problem/1697
// 큐 자료구조
class Queue {
constructor() {
this.items = {};
this.head = 0;
this.tail = 0;
}
enqueue(element) {
this.items[this.tail] = element;
this.tail++;
};
dequeue() {
const element = this.items[this.head];
delete this.items[this.head];
this.head++;
return element;
};
getLength() {
return this.tail - this.head;
}
}
let input = require('fs').readFileSync('/dev/stdin').toString().split('\n');
let [n, k] = input[0].split(' ').map(Number);
// 큐
let queue = new Queue();
queue.enqueue(n);
// 방문처리
let distTable = new Array(100_001).fill(0);
while (queue.getLength() != 0) {
let position = queue.dequeue();
if (position == k) {
console.log(distTable[position]);
break;
}
for (let i of [position-1, position+1, position*2]) {
if (distTable[i] == 0) {
distTable[i] = distTable[position] + 1;
queue.enqueue(i);
}
}
}